What are the solutions to the equation 5t^2-21t+11=-4t ?

The solutions to the equation 5t^2-21t+11=-4t are t=(17+sqrt(69))/(10),t=(17-sqrt(69))/(10)

Find the zeros of 5t^2-21t+11=-4t

The zeros of 5t^2-21t+11=-4t are t=(17+sqrt(69))/(10),t=(17-sqrt(69))/(10)

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5 t^{2} - 21 t + 11 = - 4 t

t = \frac{17 + 69}{10}, t = \frac{17 - 69}{10}

Decimal Notation

t = 2.53066 \dots, t = 0.86933 \dots

Solution steps

5 t^{2} - 21 t + 11 = - 4 t

Move

4 t

to the left side

5 t^{2} - 17 t + 11 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 5 \cdot 11}{2 \cdot 5}

(- 17)^{2} - 4 \cdot 5 \cdot 11 = 69

t_{1, 2} = \frac{- ( - 17 ) \pm 69}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- ( - 17 ) + 69}{2 \cdot 5}, t_{2} = \frac{- ( - 17 ) - 69}{2 \cdot 5}

t = \frac{- ( - 17 ) + 69}{2 \cdot 5} : \frac{17 + 69}{10}

t = \frac{- ( - 17 ) - 69}{2 \cdot 5} : \frac{17 - 69}{10}

The solutions to the quadratic equation are:

t = \frac{17 + 69}{10}, t = \frac{17 - 69}{10}

3 x^{2} + 6 x - 8 = 4 x

2 z^{2} - 2 z - 12 = 0

3 t^{2} - t - 6 = 0

x \cdot x - x = 12

2 x^{2} - 20 + 46 = 0

What are the solutions to the equation 5t^2-21t+11=-4t ?
The solutions to the equation 5t^2-21t+11=-4t are t=(17+sqrt(69))/(10),t=(17-sqrt(69))/(10)
Find the zeros of 5t^2-21t+11=-4t
The zeros of 5t^2-21t+11=-4t are t=(17+sqrt(69))/(10),t=(17-sqrt(69))/(10)