What are the solutions to the equation 4x^2+3x=24-x ?

The solutions to the equation 4x^2+3x=24-x are x=2,x=-3

Find the zeros of 4x^2+3x=24-x

The zeros of 4x^2+3x=24-x are x=2,x=-3

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4 x^{2} + 3 x = 24 - x

x = 2, x = - 3

Solution steps

4 x^{2} + 3 x = 24 - x

Move

x

to the left side

4 x^{2} + 4 x = 24

Move

24

to the left side

4 x^{2} + 4 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 24) = 20

x_{1, 2} = \frac{- 4 \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 20}{2 \cdot 4}, x_{2} = \frac{- 4 - 20}{2 \cdot 4}

x = \frac{- 4 + 20}{2 \cdot 4} : 2

x = \frac{- 4 - 20}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

5 t = t^{2}

\frac{x ^{2}}{3} - 192 = 0

3 x^{2} = 14

x^{2} = x - x^{2}

4 a^{2} + 19 a + 12 = - 5

What are the solutions to the equation 4x^2+3x=24-x ?
The solutions to the equation 4x^2+3x=24-x are x=2,x=-3
Find the zeros of 4x^2+3x=24-x
The zeros of 4x^2+3x=24-x are x=2,x=-3