What are the solutions to the equation (3m-2)(9m+5)=0 ?

The solutions to the equation (3m-2)(9m+5)=0 are m= 2/3 ,m=-5/9

Find the zeros of (3m-2)(9m+5)=0

The zeros of (3m-2)(9m+5)=0 are m= 2/3 ,m=-5/9

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(3 m - 2) (9 m + 5) = 0

m = \frac{2}{3}, m = - \frac{5}{9}

Decimal Notation

m = 0.66666 \dots, m = - 0.55555 \dots

Solution steps

(3 m - 2) (9 m + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 m - 2 = 0 or 9 m + 5 = 0

Solve

3 m - 2 = 0 : m = \frac{2}{3}

Solve

9 m + 5 = 0 : m = - \frac{5}{9}

The solutions to the quadratic equation are:

m = \frac{2}{3}, m = - \frac{5}{9}

6 r^{2} - 48 r - 54 = 0

x, x^{2} + y^{2} = 25

\frac{2}{3} x^{2} + 15 = 23

L (v) = 2 v^{2} + 50 v + 10

2 x^{2} + 16 x - 24 = 0

What are the solutions to the equation (3m-2)(9m+5)=0 ?
The solutions to the equation (3m-2)(9m+5)=0 are m= 2/3 ,m=-5/9
Find the zeros of (3m-2)(9m+5)=0
The zeros of (3m-2)(9m+5)=0 are m= 2/3 ,m=-5/9