What are the solutions to the equation a^2+1^2=4^2 ?

The solutions to the equation a^2+1^2=4^2 are a=sqrt(15),a=-sqrt(15)

Find the zeros of a^2+1^2=4^2

The zeros of a^2+1^2=4^2 are a=sqrt(15),a=-sqrt(15)

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a^{2} + 1^{2} = 4^{2}

a = 15, a = - 15

Decimal Notation

a = 3.87298 \dots, a = - 3.87298 \dots

Solution steps

a^{2} + 1^{2} = 4^{2}

Move

1^{2}

to the right side

a^{2} = 15

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 15, a = - 15

\frac{2}{3} x^{2} - 6 = 0

x, x^{2} + y^{2} = c^{2}

b x^{2} - a x = a + b

x (- 2 x - 11) = - 3

y^{2} + 6 y = 16

What are the solutions to the equation a^2+1^2=4^2 ?
The solutions to the equation a^2+1^2=4^2 are a=sqrt(15),a=-sqrt(15)
Find the zeros of a^2+1^2=4^2
The zeros of a^2+1^2=4^2 are a=sqrt(15),a=-sqrt(15)