What are the solutions to the equation 1/2 x^2+2x-1=5 ?

The solutions to the equation 1/2 x^2+2x-1=5 are x=2,x=-6

Find the zeros of 1/2 x^2+2x-1=5

The zeros of 1/2 x^2+2x-1=5 are x=2,x=-6

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\frac{1}{2} x^{2} + 2 x - 1 = 5

x = 2, x = - 6

Solution steps

\frac{1}{2} x^{2} + 2 x - 1 = 5

Multiply both sides by

2

x^{2} + 4 x - 2 = 10

Move

10

to the left side

x^{2} + 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 1}, x_{2} = \frac{- 4 - 8}{2 \cdot 1}

x = \frac{- 4 + 8}{2 \cdot 1} : 2

x = \frac{- 4 - 8}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

6 x^{2} - 12 x + 3 = 0

y^{2} = 13 y - 42

x^{2} + 20 x - 96 = 0

9 x^{2} + 12 x + 5 = 10

v, p^{1} v^{1} = p^{2} v^{2}

What are the solutions to the equation 1/2 x^2+2x-1=5 ?
The solutions to the equation 1/2 x^2+2x-1=5 are x=2,x=-6
Find the zeros of 1/2 x^2+2x-1=5
The zeros of 1/2 x^2+2x-1=5 are x=2,x=-6