What are the solutions to the equation (4x-3)(x+2)=45 ?

The solutions to the equation (4x-3)(x+2)=45 are x=3,x=-17/4

Find the zeros of (4x-3)(x+2)=45

The zeros of (4x-3)(x+2)=45 are x=3,x=-17/4

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(4 x - 3) (x + 2) = 45

x = 3, x = - \frac{17}{4}

Decimal Notation

x = 3, x = - 4.25

Solution steps

(4 x - 3) (x + 2) = 45

Expand

(4 x - 3) (x + 2) : 4 x^{2} + 5 x - 6

4 x^{2} + 5 x - 6 = 45

Move

45

to the left side

4 x^{2} + 5 x - 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 51 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 51) = 29

x_{1, 2} = \frac{- 5 \pm 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 29}{2 \cdot 4}, x_{2} = \frac{- 5 - 29}{2 \cdot 4}

x = \frac{- 5 + 29}{2 \cdot 4} : 3

x = \frac{- 5 - 29}{2 \cdot 4} : - \frac{17}{4}

The solutions to the quadratic equation are:

x = 3, x = - \frac{17}{4}

\frac{2}{3} x^{2} + 4 = 10

3^{2} = a^{2} - 4^{2}

x, 9 x^{2} + 9 y^{2} + 9 z^{2} + 9 x - 36 z + 27 = 0

2 x^{2} + 26 = 12 x

\frac{x ^{2}}{3} - x = \frac{5}{6}

What are the solutions to the equation (4x-3)(x+2)=45 ?
The solutions to the equation (4x-3)(x+2)=45 are x=3,x=-17/4
Find the zeros of (4x-3)(x+2)=45
The zeros of (4x-3)(x+2)=45 are x=3,x=-17/4