What are the solutions to the equation 3^2=a^2-4^2 ?

The solutions to the equation 3^2=a^2-4^2 are a=5,a=-5

Find the zeros of 3^2=a^2-4^2

The zeros of 3^2=a^2-4^2 are a=5,a=-5

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3^{2} = a^{2} - 4^{2}

a = 5, a = - 5

Solution steps

3^{2} = a^{2} - 4^{2}

Switch sides

a^{2} - 4^{2} = 3^{2}

Move

4^{2}

to the right side

a^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 25, a = - 25

25 = 5

- 25 = - 5

a = 5, a = - 5

x, 9 x^{2} + 9 y^{2} + 9 z^{2} + 9 x - 36 z + 27 = 0

2 x^{2} + 26 = 12 x

\frac{x ^{2}}{3} - x = \frac{5}{6}

x^{2} - 19 x + 32 = 0

2 x^{2} + 8 x - 9 = 0

What are the solutions to the equation 3^2=a^2-4^2 ?
The solutions to the equation 3^2=a^2-4^2 are a=5,a=-5
Find the zeros of 3^2=a^2-4^2
The zeros of 3^2=a^2-4^2 are a=5,a=-5