What are the solutions to the equation λ^2-6λ+9(1)=0 ?

The solutions to the equation λ^2-6λ+9(1)=0 are λ=3

Find the zeros of λ^2-6λ+9(1)=0

The zeros of λ^2-6λ+9(1)=0 are λ=3

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λ^{2} - 6 λ + 9 (1) = 0

λ = 3

Solution steps

λ^{2} - 6 λ + 9 (1) = 0

Expand

λ^{2} - 6 λ + 9 (1) : λ^{2} - 6 λ + 9

λ^{2} - 6 λ + 9 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

λ_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

λ = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

λ = 3

The solution to the quadratic equation is:

λ = 3

- 7 x^{2} + 6 x + 3 = 0

6 x = 27 - x^{2}

(x + 5) (x - 2) = - 12

12 + 0.3 q = 111 - 0.1 q^{2}

x, 3 x^{2} y = x + 9

What are the solutions to the equation λ^2-6λ+9(1)=0 ?
The solutions to the equation λ^2-6λ+9(1)=0 are λ=3
Find the zeros of λ^2-6λ+9(1)=0
The zeros of λ^2-6λ+9(1)=0 are λ=3