What are the solutions to the equation 5x^2+13x-6=10x-4 ?

The solutions to the equation 5x^2+13x-6=10x-4 are x= 2/5 ,x=-1

Find the zeros of 5x^2+13x-6=10x-4

The zeros of 5x^2+13x-6=10x-4 are x= 2/5 ,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 13 x - 6 = 10 x - 4

x = \frac{2}{5}, x = - 1

Decimal Notation

x = 0.4, x = - 1

Solution steps

5 x^{2} + 13 x - 6 = 10 x - 4

Move

4

to the left side

5 x^{2} + 13 x - 2 = 10 x

Move

10 x

to the left side

5 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 2) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 5}, x_{2} = \frac{- 3 - 7}{2 \cdot 5}

x = \frac{- 3 + 7}{2 \cdot 5} : \frac{2}{5}

x = \frac{- 3 - 7}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - 1

- 2 (x + 3) (7 x + 5) = 0

x^{2} + 5 x - 300 = 0

1927.8 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

(X + 3)^{2} - (X - 1)^{2} = X^{2}

2 x^{2} - 8 x + 8 = 0

What are the solutions to the equation 5x^2+13x-6=10x-4 ?
The solutions to the equation 5x^2+13x-6=10x-4 are x= 2/5 ,x=-1
Find the zeros of 5x^2+13x-6=10x-4
The zeros of 5x^2+13x-6=10x-4 are x= 2/5 ,x=-1