What are the solutions to the equation 5x^2-40x+5=0 ?

The solutions to the equation 5x^2-40x+5=0 are x=4+sqrt(15),x=4-sqrt(15)

Find the zeros of 5x^2-40x+5=0

The zeros of 5x^2-40x+5=0 are x=4+sqrt(15),x=4-sqrt(15)

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5 x^{2} - 40 x + 5 = 0

x = 4 + 15, x = 4 - 15

Decimal Notation

x = 7.87298 \dots, x = 0.12701 \dots

Solution steps

5 x^{2} - 40 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

(- 40)^{2} - 4 \cdot 5 \cdot 5 = 1015

x_{1, 2} = \frac{- ( - 40 ) \pm 10 15}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 10 15}{2 \cdot 5}, x_{2} = \frac{- ( - 40 ) - 10 15}{2 \cdot 5}

x = \frac{- ( - 40 ) + 10 15}{2 \cdot 5} : 4 + 15

x = \frac{- ( - 40 ) - 10 15}{2 \cdot 5} : 4 - 15

The solutions to the quadratic equation are:

x = 4 + 15, x = 4 - 15

5 x^{2} - 4 x - 6 = x^{2} - 7

5 x^{2} = 10 x + 15

x, x^{2} - x y = 0

3 x^{2} + 2 x + a x^{2} + 5 a + 1 = 0

x, (2 x + 3 y)^{2} = 20

What are the solutions to the equation 5x^2-40x+5=0 ?
The solutions to the equation 5x^2-40x+5=0 are x=4+sqrt(15),x=4-sqrt(15)
Find the zeros of 5x^2-40x+5=0
The zeros of 5x^2-40x+5=0 are x=4+sqrt(15),x=4-sqrt(15)