What are the solutions to the equation 12^2+b^2=18^2 ?

The solutions to the equation 12^2+b^2=18^2 are b=6sqrt(5),b=-6sqrt(5)

Find the zeros of 12^2+b^2=18^2

The zeros of 12^2+b^2=18^2 are b=6sqrt(5),b=-6sqrt(5)

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1 2^{2} + b^{2} = 1 8^{2}

b = 65, b = - 65

Decimal Notation

b = 13.41640 \dots, b = - 13.41640 \dots

Solution steps

1 2^{2} + b^{2} = 1 8^{2}

Move

1 2^{2}

to the right side

b^{2} = 180

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 180, b = - 180

180 = 65

- 180 = - 65

b = 65, b = - 65

- 4 x^{2} + 2 x + 8 = 0

x^{2} + 6 = - 5 x

3 x^{2} - 30 x - 33 = 0

x, g = 3 x^{2} f

x^{2} - 3 x - 270 = 0

What are the solutions to the equation 12^2+b^2=18^2 ?
The solutions to the equation 12^2+b^2=18^2 are b=6sqrt(5),b=-6sqrt(5)
Find the zeros of 12^2+b^2=18^2
The zeros of 12^2+b^2=18^2 are b=6sqrt(5),b=-6sqrt(5)