What are the solutions to the equation 12x^2+3-12x=0 ?

The solutions to the equation 12x^2+3-12x=0 are x= 1/2

Find the zeros of 12x^2+3-12x=0

The zeros of 12x^2+3-12x=0 are x= 1/2

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12 x^{2} + 3 - 12 x = 0

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

12 x^{2} + 3 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

(- 12)^{2} - 4 \cdot 12 \cdot 3 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 12}

x = \frac{- ( - 12 )}{2 \cdot 12}

\frac{- ( - 12 )}{2 \cdot 12} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

3 (t - 2)^{2} = t (t + 5) + 4

3 x^{2} - 6 x + c = 0

x, f (x + 3) = g (x^{2})

x^{2} + 86 x + 168 = 0

x, z = x^{2} - 2 y^{2}

What are the solutions to the equation 12x^2+3-12x=0 ?
The solutions to the equation 12x^2+3-12x=0 are x= 1/2
Find the zeros of 12x^2+3-12x=0
The zeros of 12x^2+3-12x=0 are x= 1/2