What are the solutions to the equation 3x^2-6x+c=0 ?

The solutions to the equation 3x^2-6x+c=0 are x=(6+sqrt(36-12c))/6 ,x=(6-sqrt(36-12c))/6

Find the zeros of 3x^2-6x+c=0

The zeros of 3x^2-6x+c=0 are x=(6+sqrt(36-12c))/6 ,x=(6-sqrt(36-12c))/6

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3 x^{2} - 6 x + c = 0

x = \frac{6 + 36 - 12 c}{6}, x = \frac{6 - 36 - 12 c}{6}

Solution steps

3 x^{2} - 6 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 c}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 c : 36 - 12 c

x_{1, 2} = \frac{- ( - 6 ) \pm 36 - 12 c}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 36 - 12 c}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 36 - 12 c}{2 \cdot 3}

x = \frac{- ( - 6 ) + 36 - 12 c}{2 \cdot 3} : \frac{6 + 36 - 12 c}{6}

x = \frac{- ( - 6 ) - 36 - 12 c}{2 \cdot 3} : \frac{6 - 36 - 12 c}{6}

The solutions to the quadratic equation are:

x = \frac{6 + 36 - 12 c}{6}, x = \frac{6 - 36 - 12 c}{6}

x, f (x + 3) = g (x^{2})

x^{2} + 86 x + 168 = 0

x, z = x^{2} - 2 y^{2}

3 x^{2} - (m + 1) x + m - 2 = 0

\frac{5 x ^{2}}{3} + 61 = 121

What are the solutions to the equation 3x^2-6x+c=0 ?
The solutions to the equation 3x^2-6x+c=0 are x=(6+sqrt(36-12c))/6 ,x=(6-sqrt(36-12c))/6
Find the zeros of 3x^2-6x+c=0
The zeros of 3x^2-6x+c=0 are x=(6+sqrt(36-12c))/6 ,x=(6-sqrt(36-12c))/6