What are the solutions to the equation x^2+86x+168=0 ?

The solutions to the equation x^2+86x+168=0 are x=-2,x=-84

Find the zeros of x^2+86x+168=0

The zeros of x^2+86x+168=0 are x=-2,x=-84

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x^{2} + 86 x + 168 = 0

x = - 2, x = - 84

Solution steps

x^{2} + 86 x + 168 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 86 \pm 8 6 ^{2} - 4 \cdot 1 \cdot 168}{2 \cdot 1}

8 6^{2} - 4 \cdot 1 \cdot 168 = 82

x_{1, 2} = \frac{- 86 \pm 82}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 86 + 82}{2 \cdot 1}, x_{2} = \frac{- 86 - 82}{2 \cdot 1}

x = \frac{- 86 + 82}{2 \cdot 1} : - 2

x = \frac{- 86 - 82}{2 \cdot 1} : - 84

The solutions to the quadratic equation are:

x = - 2, x = - 84

x, z = x^{2} - 2 y^{2}

3 x^{2} - (m + 1) x + m - 2 = 0

\frac{5 x ^{2}}{3} + 61 = 121

- 0.012 x^{2} + 220 = 0.001 x^{2} + 0.12 x + 220

12 x^{2} = 48

What are the solutions to the equation x^2+86x+168=0 ?
The solutions to the equation x^2+86x+168=0 are x=-2,x=-84
Find the zeros of x^2+86x+168=0
The zeros of x^2+86x+168=0 are x=-2,x=-84