What are the solutions to the equation 0= 1/2 x^2+2x+6 ?

The solutions to the equation 0= 1/2 x^2+2x+6 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

Find the zeros of 0= 1/2 x^2+2x+6

The zeros of 0= 1/2 x^2+2x+6 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

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0 = \frac{1}{2} x^{2} + 2 x + 6

x = - 2 + 22 i, x = - 2 - 22 i

Solution steps

0 = \frac{1}{2} x^{2} + 2 x + 6

Multiply both sides by

2

0 = x^{2} + 4 x + 12

Switch sides

x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 12 : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 2 i}{2 \cdot 1}

x = \frac{- 4 + 4 2 i}{2 \cdot 1} : - 2 + 22 i

x = \frac{- 4 - 4 2 i}{2 \cdot 1} : - 2 - 22 i

The solutions to the quadratic equation are:

x = - 2 + 22 i, x = - 2 - 22 i

8 x^{2} = 15 - 3 x

\frac{x ^{2} - 36}{8} + \frac{x ^{2} - 64}{6} = 14

x (x + 3) = 5 x

\frac{2}{15} x^{2} + (- \frac{1}{6} + \frac{1}{10}) x = \frac{1}{8}

λ^{2} + 4 λ - 5 (1) = 0

What are the solutions to the equation 0= 1/2 x^2+2x+6 ?
The solutions to the equation 0= 1/2 x^2+2x+6 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i
Find the zeros of 0= 1/2 x^2+2x+6
The zeros of 0= 1/2 x^2+2x+6 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i