What are the solutions to the equation 8x^2=15-3x ?

The solutions to the equation 8x^2=15-3x are x=(-3+sqrt(489))/(16),x=(-3-sqrt(489))/(16)

Find the zeros of 8x^2=15-3x

The zeros of 8x^2=15-3x are x=(-3+sqrt(489))/(16),x=(-3-sqrt(489))/(16)

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8 x^{2} = 15 - 3 x

x = \frac{- 3 + 489}{16}, x = \frac{- 3 - 489}{16}

Decimal Notation

x = 1.19458 \dots, x = - 1.56958 \dots

Solution steps

8 x^{2} = 15 - 3 x

Move

3 x

to the left side

8 x^{2} + 3 x = 15

Move

15

to the left side

8 x^{2} + 3 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 8 ( - 15 )}{2 \cdot 8}

3^{2} - 4 \cdot 8 (- 15) = 489

x_{1, 2} = \frac{- 3 \pm 489}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 3 + 489}{2 \cdot 8}, x_{2} = \frac{- 3 - 489}{2 \cdot 8}

x = \frac{- 3 + 489}{2 \cdot 8} : \frac{- 3 + 489}{16}

x = \frac{- 3 - 489}{2 \cdot 8} : \frac{- 3 - 489}{16}

The solutions to the quadratic equation are:

x = \frac{- 3 + 489}{16}, x = \frac{- 3 - 489}{16}

\frac{x ^{2} - 36}{8} + \frac{x ^{2} - 64}{6} = 14

x (x + 3) = 5 x

\frac{2}{15} x^{2} + (- \frac{1}{6} + \frac{1}{10}) x = \frac{1}{8}

λ^{2} + 4 λ - 5 (1) = 0

x^{2} - 16 x + 16 = 2 x - 20

What are the solutions to the equation 8x^2=15-3x ?
The solutions to the equation 8x^2=15-3x are x=(-3+sqrt(489))/(16),x=(-3-sqrt(489))/(16)
Find the zeros of 8x^2=15-3x
The zeros of 8x^2=15-3x are x=(-3+sqrt(489))/(16),x=(-3-sqrt(489))/(16)