What are the solutions to the equation 0=-2x^2+6x ?

The solutions to the equation 0=-2x^2+6x are x=0,x=3

Find the zeros of 0=-2x^2+6x

The zeros of 0=-2x^2+6x are x=0,x=3

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0 = - 2 x^{2} + 6 x

x = 0, x = 3

Solution steps

0 = - 2 x^{2} + 6 x

Switch sides

- 2 x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

6^{2} - 4 (- 2) \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 ( - 2 )}, x_{2} = \frac{- 6 - 6}{2 ( - 2 )}

x = \frac{- 6 + 6}{2 ( - 2 )} : 0

x = \frac{- 6 - 6}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

4 x^{2} + 12 x + 32 = 0

(x - 2)^{2} + (\frac{4}{3} x + \frac{4}{3} - 4)^{2} = 16

(x + 3) (x + 5) = 48

4 p^{2} - 4 = 0

x^{2} + 4 x + x = 0

What are the solutions to the equation 0=-2x^2+6x ?
The solutions to the equation 0=-2x^2+6x are x=0,x=3
Find the zeros of 0=-2x^2+6x
The zeros of 0=-2x^2+6x are x=0,x=3