What are the solutions to the equation 2x^2-10x-20=0 ?

The solutions to the equation 2x^2-10x-20=0 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2

Find the zeros of 2x^2-10x-20=0

The zeros of 2x^2-10x-20=0 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2

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2 x^{2} - 10 x - 20 = 0

x = \frac{5 + 65}{2}, x = \frac{5 - 65}{2}

Decimal Notation

x = 6.53112 \dots, x = - 1.53112 \dots

Solution steps

2 x^{2} - 10 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 (- 20) = 265

x_{1, 2} = \frac{- ( - 10 ) \pm 2 65}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 65}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 65}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 65}{2 \cdot 2} : \frac{5 + 65}{2}

x = \frac{- ( - 10 ) - 2 65}{2 \cdot 2} : \frac{5 - 65}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 65}{2}, x = \frac{5 - 65}{2}

x, y^{2} - 2 y - 4 x^{2} - 16 x = 15

x, z = 2 x^{2} - 3 x y + 4 y^{2}

- 4 x^{2} - 8 x + 5 = 0

x^{2} + 4 = - 2 x + 3

- x^{2} + 4 x + 3 = x - 1

What are the solutions to the equation 2x^2-10x-20=0 ?
The solutions to the equation 2x^2-10x-20=0 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2
Find the zeros of 2x^2-10x-20=0
The zeros of 2x^2-10x-20=0 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2