What are the solutions to the equation solvefor x,y^2-x^2=c ?

The solutions to the equation solvefor x,y^2-x^2=c are x=sqrt(-c+y^2),x=-sqrt(-c+y^2)

Find the zeros of solvefor x,y^2-x^2=c

The zeros of solvefor x,y^2-x^2=c are x=sqrt(-c+y^2),x=-sqrt(-c+y^2)

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solve for

x, y^{2} - x^{2} = c

x = - c + y^{2}, x = - - c + y^{2}

Solution steps

y^{2} - x^{2} = c

Move

y^{2}

to the right side

- x^{2} = c - y^{2}

Divide both sides by

- 1

x^{2} = - c + y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - c + y^{2}, x = - - c + y^{2}

3 x^{2} - 7 x + 2 = 0

x^{2} + \frac{18}{5} x + \frac{81}{25} = 0

(2 x - 3) (x - 2) = 5

100 - x^{2} = x^{2} + 4 x + 4

a^{2} + 1 6^{2} = 1 8^{2}

What are the solutions to the equation solvefor x,y^2-x^2=c ?
The solutions to the equation solvefor x,y^2-x^2=c are x=sqrt(-c+y^2),x=-sqrt(-c+y^2)
Find the zeros of solvefor x,y^2-x^2=c
The zeros of solvefor x,y^2-x^2=c are x=sqrt(-c+y^2),x=-sqrt(-c+y^2)