What are the solutions to the equation 100-x^2=x^2+4x+4 ?

The solutions to the equation 100-x^2=x^2+4x+4 are x=6,x=-8

Find the zeros of 100-x^2=x^2+4x+4

The zeros of 100-x^2=x^2+4x+4 are x=6,x=-8

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100 - x^{2} = x^{2} + 4 x + 4

x = 6, x = - 8

Solution steps

100 - x^{2} = x^{2} + 4 x + 4

Switch sides

x^{2} + 4 x + 4 = 100 - x^{2}

Move

x^{2}

to the left side

2 x^{2} + 4 x + 4 = 100

Move

100

to the left side

2 x^{2} + 4 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 96 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 96) = 28

x_{1, 2} = \frac{- 4 \pm 28}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 28}{2 \cdot 2}, x_{2} = \frac{- 4 - 28}{2 \cdot 2}

x = \frac{- 4 + 28}{2 \cdot 2} : 6

x = \frac{- 4 - 28}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = 6, x = - 8

a^{2} + 1 6^{2} = 1 8^{2}

n^{2} + 3 n - 28 = 0

3 + 5 x - 2 x^{2} = 0

6 x^{2} + 9 x + 2 = - 2 - 4 x - 3 x^{2}

6 p - 6 = p^{2}

What are the solutions to the equation 100-x^2=x^2+4x+4 ?
The solutions to the equation 100-x^2=x^2+4x+4 are x=6,x=-8
Find the zeros of 100-x^2=x^2+4x+4
The zeros of 100-x^2=x^2+4x+4 are x=6,x=-8