What are the solutions to the equation m^2+6m=-8 ?

The solutions to the equation m^2+6m=-8 are m=-2,m=-4

Find the zeros of m^2+6m=-8

The zeros of m^2+6m=-8 are m=-2,m=-4

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m^{2} + 6 m = - 8

m = - 2, m = - 4

Solution steps

m^{2} + 6 m = - 8

Move

8

to the left side

m^{2} + 6 m + 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

m_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 6 + 2}{2 \cdot 1}, m_{2} = \frac{- 6 - 2}{2 \cdot 1}

m = \frac{- 6 + 2}{2 \cdot 1} : - 2

m = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

m = - 2, m = - 4

x^{2} + 10 x - 3

- 6 = x^{2} + 4 x - 1

x, y^{2} + 2 x y + 6 x^{2} = 8

4 + 6 x - 9 x^{2} = 0

(- 2 y - 1)^{2} + (y - 1)^{2} = 5

What are the solutions to the equation m^2+6m=-8 ?
The solutions to the equation m^2+6m=-8 are m=-2,m=-4
Find the zeros of m^2+6m=-8
The zeros of m^2+6m=-8 are m=-2,m=-4