What are the solutions to the equation 7x^2=-9x-3 ?

The solutions to the equation 7x^2=-9x-3 are x=-9/14+i(sqrt(3))/(14),x=-9/14-i(sqrt(3))/(14)

Find the zeros of 7x^2=-9x-3

The zeros of 7x^2=-9x-3 are x=-9/14+i(sqrt(3))/(14),x=-9/14-i(sqrt(3))/(14)

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7 x^{2} = - 9 x - 3

x = - \frac{9}{14} + i \frac{3}{14}, x = - \frac{9}{14} - i \frac{3}{14}

Solution steps

7 x^{2} = - 9 x - 3

Move

3

to the left side

7 x^{2} + 3 = - 9 x

Move

9 x

to the left side

7 x^{2} + 3 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} + 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 7 \cdot 3}{2 \cdot 7}

Simplify

9^{2} - 4 \cdot 7 \cdot 3 : 3 i

x_{1, 2} = \frac{- 9 \pm 3 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 9 + 3 i}{2 \cdot 7}, x_{2} = \frac{- 9 - 3 i}{2 \cdot 7}

x = \frac{- 9 + 3 i}{2 \cdot 7} : - \frac{9}{14} + i \frac{3}{14}

x = \frac{- 9 - 3 i}{2 \cdot 7} : - \frac{9}{14} - i \frac{3}{14}

The solutions to the quadratic equation are:

x = - \frac{9}{14} + i \frac{3}{14}, x = - \frac{9}{14} - i \frac{3}{14}

m^{2} + 6 m = - 8

x^{2} + 10 x - 3

- 6 = x^{2} + 4 x - 1

x, y^{2} + 2 x y + 6 x^{2} = 8

4 + 6 x - 9 x^{2} = 0

What are the solutions to the equation 7x^2=-9x-3 ?
The solutions to the equation 7x^2=-9x-3 are x=-9/14+i(sqrt(3))/(14),x=-9/14-i(sqrt(3))/(14)
Find the zeros of 7x^2=-9x-3
The zeros of 7x^2=-9x-3 are x=-9/14+i(sqrt(3))/(14),x=-9/14-i(sqrt(3))/(14)