What are the solutions to the equation x^2+11ax+10a^2=0 ?

The solutions to the equation x^2+11ax+10a^2=0 are x=-a,x=-10a

Find the zeros of x^2+11ax+10a^2=0

The zeros of x^2+11ax+10a^2=0 are x=-a,x=-10a

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x^{2} + 11 a x + 10 a^{2} = 0

x = - a, x = - 10 a

Solution steps

x^{2} + 11 a x + 10 a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 a \pm ( 11 a ) ^{2} - 4 \cdot 1 \cdot 10 a ^{2}}{2 \cdot 1}

Simplify

(11 a)^{2} - 4 \cdot 1 \cdot 10 a^{2} : 9 a

x_{1, 2} = \frac{- 11 a \pm 9 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 a + 9 a}{2 \cdot 1}, x_{2} = \frac{- 11 a - 9 a}{2 \cdot 1}

x = \frac{- 11 a + 9 a}{2 \cdot 1} : - a

x = \frac{- 11 a - 9 a}{2 \cdot 1} : - 10 a

The solutions to the quadratic equation are:

x = - a, x = - 10 a

x^{2} - x - 6 = - 4

0 = 5 x^{2} - 20 x + 4

3 k^{2} + k - 11 = - 4

6 x^{2} - 14 = 0

(x - 3) (x - 2) = (x + 5) (2 x - 3) + 21

What are the solutions to the equation x^2+11ax+10a^2=0 ?
The solutions to the equation x^2+11ax+10a^2=0 are x=-a,x=-10a
Find the zeros of x^2+11ax+10a^2=0
The zeros of x^2+11ax+10a^2=0 are x=-a,x=-10a