What are the solutions to the equation x^2-14x+4=-10x+9 ?

The solutions to the equation x^2-14x+4=-10x+9 are x=5,x=-1

Find the zeros of x^2-14x+4=-10x+9

The zeros of x^2-14x+4=-10x+9 are x=5,x=-1

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x^{2} - 14 x + 4 = - 10 x + 9

x = 5, x = - 1

Solution steps

x^{2} - 14 x + 4 = - 10 x + 9

Move

9

to the left side

x^{2} - 14 x - 5 = - 10 x

Move

10 x

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

x, x^{2} + x y + y^{2} = c

x^{2} - x + 1 = 2

- 10 x^{2} - 4 x + 2 = 0

1 + 0.2 x + 0.7 x^{2} = 0

\frac{1}{6} n^{2} - \frac{1}{2} n - \frac{2}{3} = 0

What are the solutions to the equation x^2-14x+4=-10x+9 ?
The solutions to the equation x^2-14x+4=-10x+9 are x=5,x=-1
Find the zeros of x^2-14x+4=-10x+9
The zeros of x^2-14x+4=-10x+9 are x=5,x=-1