What are the solutions to the equation 3x^2-688x+25300=0 ?

The solutions to the equation 3x^2-688x+25300=0 are x= 550/3 ,x=46

Find the zeros of 3x^2-688x+25300=0

The zeros of 3x^2-688x+25300=0 are x= 550/3 ,x=46

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3 x^{2} - 688 x + 25300 = 0

x = \frac{550}{3}, x = 46

Decimal Notation

x = 183.33333 \dots, x = 46

Solution steps

3 x^{2} - 688 x + 25300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 688 ) \pm ( - 688 ) ^{2} - 4 \cdot 3 \cdot 25300}{2 \cdot 3}

(- 688)^{2} - 4 \cdot 3 \cdot 25300 = 412

x_{1, 2} = \frac{- ( - 688 ) \pm 412}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 688 ) + 412}{2 \cdot 3}, x_{2} = \frac{- ( - 688 ) - 412}{2 \cdot 3}

x = \frac{- ( - 688 ) + 412}{2 \cdot 3} : \frac{550}{3}

x = \frac{- ( - 688 ) - 412}{2 \cdot 3} : 46

The solutions to the quadratic equation are:

x = \frac{550}{3}, x = 46

r = 4 r^{2} - 1

x^{2} + 2 x + 100 = 0

y^{2} + 11 y + 28 = 0

6 x^{2} - 23 x - 18 = 0

2 x^{2} + 5 x - 250 = 0

What are the solutions to the equation 3x^2-688x+25300=0 ?
The solutions to the equation 3x^2-688x+25300=0 are x= 550/3 ,x=46
Find the zeros of 3x^2-688x+25300=0
The zeros of 3x^2-688x+25300=0 are x= 550/3 ,x=46