What are the solutions to the equation x^2+14x+49=7 ?

The solutions to the equation x^2+14x+49=7 are x=-7+sqrt(7),x=-7-sqrt(7)

Find the zeros of x^2+14x+49=7

The zeros of x^2+14x+49=7 are x=-7+sqrt(7),x=-7-sqrt(7)

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x^{2} + 14 x + 49 = 7

x = - 7 + 7, x = - 7 - 7

Decimal Notation

x = - 4.35424 \dots, x = - 9.64575 \dots

Solution steps

x^{2} + 14 x + 49 = 7

Move

7

to the left side

x^{2} + 14 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 42 = 27

x_{1, 2} = \frac{- 14 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 7}{2 \cdot 1}

x = \frac{- 14 + 2 7}{2 \cdot 1} : - 7 + 7

x = \frac{- 14 - 2 7}{2 \cdot 1} : - 7 - 7

The solutions to the quadratic equation are:

x = - 7 + 7, x = - 7 - 7

0 = 2 x^{2} + 8 x

(2 x + 6)^{2} = 36

900 = w (2 w - 5)

2 (x - 4)^{2} = 18

x^{2} + 3 x = - \frac{1}{4}

What are the solutions to the equation x^2+14x+49=7 ?
The solutions to the equation x^2+14x+49=7 are x=-7+sqrt(7),x=-7-sqrt(7)
Find the zeros of x^2+14x+49=7
The zeros of x^2+14x+49=7 are x=-7+sqrt(7),x=-7-sqrt(7)