What are the solutions to the equation -3x^2+48x=0 ?

The solutions to the equation -3x^2+48x=0 are x=0,x=16

Find the zeros of -3x^2+48x=0

The zeros of -3x^2+48x=0 are x=0,x=16

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- 3 x^{2} + 48 x = 0

x = 0, x = 16

Solution steps

- 3 x^{2} + 48 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

4 8^{2} - 4 (- 3) \cdot 0 = 48

x_{1, 2} = \frac{- 48 \pm 48}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 48 + 48}{2 ( - 3 )}, x_{2} = \frac{- 48 - 48}{2 ( - 3 )}

x = \frac{- 48 + 48}{2 ( - 3 )} : 0

x = \frac{- 48 - 48}{2 ( - 3 )} : 16

The solutions to the quadratic equation are:

x = 0, x = 16

m^{2} - 2 m - 1 = 0

x, 2 x^{2} + 4 x + 8 = - y^{2}

((x^{2}) + 5) + x = 80

4 x^{2} - 16 x - 24 = 0

- x^{2} - x - 5 = 0

What are the solutions to the equation -3x^2+48x=0 ?
The solutions to the equation -3x^2+48x=0 are x=0,x=16
Find the zeros of -3x^2+48x=0
The zeros of -3x^2+48x=0 are x=0,x=16