What are the solutions to the equation 4x^2-16x-24=0 ?

The solutions to the equation 4x^2-16x-24=0 are x=2+sqrt(10),x=2-sqrt(10)

Find the zeros of 4x^2-16x-24=0

The zeros of 4x^2-16x-24=0 are x=2+sqrt(10),x=2-sqrt(10)

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4 x^{2} - 16 x - 24 = 0

x = 2 + 10, x = 2 - 10

Decimal Notation

x = 5.16227 \dots, x = - 1.16227 \dots

Solution steps

4 x^{2} - 16 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 (- 24) = 810

x_{1, 2} = \frac{- ( - 16 ) \pm 8 10}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8 10}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 8 10}{2 \cdot 4}

x = \frac{- ( - 16 ) + 8 10}{2 \cdot 4} : 2 + 10

x = \frac{- ( - 16 ) - 8 10}{2 \cdot 4} : 2 - 10

The solutions to the quadratic equation are:

x = 2 + 10, x = 2 - 10

- x^{2} - x - 5 = 0

x, x^{2} + 10 x + 12 = 36

2 x^{2} + 27 x - 14 = 0

- 6 x = x^{2} + 8

x^{2} + 2 x = - 17

What are the solutions to the equation 4x^2-16x-24=0 ?
The solutions to the equation 4x^2-16x-24=0 are x=2+sqrt(10),x=2-sqrt(10)
Find the zeros of 4x^2-16x-24=0
The zeros of 4x^2-16x-24=0 are x=2+sqrt(10),x=2-sqrt(10)