What are the solutions to the equation 4x^2+63x-16=0 ?

The solutions to the equation 4x^2+63x-16=0 are x= 1/4 ,x=-16

Find the zeros of 4x^2+63x-16=0

The zeros of 4x^2+63x-16=0 are x= 1/4 ,x=-16

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4 x^{2} + 63 x - 16 = 0

x = \frac{1}{4}, x = - 16

Decimal Notation

x = 0.25, x = - 16

Solution steps

4 x^{2} + 63 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 63 \pm 6 3 ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

6 3^{2} - 4 \cdot 4 (- 16) = 65

x_{1, 2} = \frac{- 63 \pm 65}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 63 + 65}{2 \cdot 4}, x_{2} = \frac{- 63 - 65}{2 \cdot 4}

x = \frac{- 63 + 65}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 63 - 65}{2 \cdot 4} : - 16

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 16

x, f (x + h) = (x + h)^{2}

a, a^{2} + b^{2} + c^{2} + (a + b + c)^{2} = 202 2^{2}

X^{2} + 8 X + 16 = 0

x^{2} + 4 x + \frac{1}{2} = 0

x, z = 4 x^{2} + y^{2} + 1

What are the solutions to the equation 4x^2+63x-16=0 ?
The solutions to the equation 4x^2+63x-16=0 are x= 1/4 ,x=-16
Find the zeros of 4x^2+63x-16=0
The zeros of 4x^2+63x-16=0 are x= 1/4 ,x=-16