What are the solutions to the equation d^2=x^2+x^2 ?

The solutions to the equation d^2=x^2+x^2 are x= d/(sqrt(2)),x=-d/(sqrt(2))

Find the zeros of d^2=x^2+x^2

The zeros of d^2=x^2+x^2 are x= d/(sqrt(2)),x=-d/(sqrt(2))

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d^{2} = x^{2} + x^{2}

x = \frac{d}{2}, x = - \frac{d}{2}

Solution steps

d^{2} = x^{2} + x^{2}

Switch sides

x^{2} + x^{2} = d^{2}

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} = d^{2}

Divide both sides by

2

x^{2} = \frac{d ^{2}}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{d ^{2}}{2}, x = - \frac{d ^{2}}{2}

Simplify

\frac{d ^{2}}{2} : \frac{d}{2}

Simplify

- \frac{d ^{2}}{2} : - \frac{d}{2}

x = \frac{d}{2}, x = - \frac{d}{2}

- 2 x (x - 2) = 3 (x + 2)

- 3 s^{2} - 30 s - 50 = 0

x, f (x^{2} + x + 2) = f + 1

\frac{1}{4} (7 - 4 x^{2}) + 4 x + \frac{1 - 8 x}{2} = 0

x, x^{2} = 4 y^{2}

What are the solutions to the equation d^2=x^2+x^2 ?
The solutions to the equation d^2=x^2+x^2 are x= d/(sqrt(2)),x=-d/(sqrt(2))
Find the zeros of d^2=x^2+x^2
The zeros of d^2=x^2+x^2 are x= d/(sqrt(2)),x=-d/(sqrt(2))