What are the solutions to the equation x^2+1=3-x^2 ?

The solutions to the equation x^2+1=3-x^2 are x=1,x=-1

Find the zeros of x^2+1=3-x^2

The zeros of x^2+1=3-x^2 are x=1,x=-1

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x^{2} + 1 = 3 - x^{2}

x = 1, x = - 1

Solution steps

x^{2} + 1 = 3 - x^{2}

Move

1

to the right side

x^{2} = - x^{2} + 2

Move

x^{2}

to the left side

2 x^{2} = 2

Divide both sides by

2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

t^{2} - 3 t - 2 = 0

x, (x - m)^{2} = 6 - m

(2 x + 15) (9 + 2 x) - (15) (9) = 100

x^{2} + 8 (\frac{- 8 - 3 x}{4}) = 0

(x + 6)^{2} + 3 (5 x - 6) = - 2 (x^{2} + x)

What are the solutions to the equation x^2+1=3-x^2 ?
The solutions to the equation x^2+1=3-x^2 are x=1,x=-1
Find the zeros of x^2+1=3-x^2
The zeros of x^2+1=3-x^2 are x=1,x=-1