What are the solutions to the equation 36x^2-24x-12=0 ?

The solutions to the equation 36x^2-24x-12=0 are x=1,x=-1/3

Find the zeros of 36x^2-24x-12=0

The zeros of 36x^2-24x-12=0 are x=1,x=-1/3

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36 x^{2} - 24 x - 12 = 0

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

36 x^{2} - 24 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 36 ( - 12 )}{2 \cdot 36}

(- 24)^{2} - 4 \cdot 36 (- 12) = 48

x_{1, 2} = \frac{- ( - 24 ) \pm 48}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 48}{2 \cdot 36}, x_{2} = \frac{- ( - 24 ) - 48}{2 \cdot 36}

x = \frac{- ( - 24 ) + 48}{2 \cdot 36} : 1

x = \frac{- ( - 24 ) - 48}{2 \cdot 36} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

x, b^{2} x^{2} - a^{2} y^{2} = 3 a^{2} b^{2}

x^{2} - 9 x - 43 = 27

- 2 x^{2} + 2 x + 15 = 0

G (x) = - 0.003 x^{2} + 6 x - 1700

9 x^{2} - 18 x + 13

What are the solutions to the equation 36x^2-24x-12=0 ?
The solutions to the equation 36x^2-24x-12=0 are x=1,x=-1/3
Find the zeros of 36x^2-24x-12=0
The zeros of 36x^2-24x-12=0 are x=1,x=-1/3