What are the solutions to the equation x^2-9x-43=27 ?

The solutions to the equation x^2-9x-43=27 are x=14,x=-5

Find the zeros of x^2-9x-43=27

The zeros of x^2-9x-43=27 are x=14,x=-5

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x^{2} - 9 x - 43 = 27

x = 14, x = - 5

Solution steps

x^{2} - 9 x - 43 = 27

Move

27

to the left side

x^{2} - 9 x - 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 70 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 70) = 19

x_{1, 2} = \frac{- ( - 9 ) \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 19}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 19}{2 \cdot 1}

x = \frac{- ( - 9 ) + 19}{2 \cdot 1} : 14

x = \frac{- ( - 9 ) - 19}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 14, x = - 5

- 2 x^{2} + 2 x + 15 = 0

G (x) = - 0.003 x^{2} + 6 x - 1700

9 x^{2} - 18 x + 13

- x^{2} - 13 x = 6

3 x^{2} - 6 x + 12

What are the solutions to the equation x^2-9x-43=27 ?
The solutions to the equation x^2-9x-43=27 are x=14,x=-5
Find the zeros of x^2-9x-43=27
The zeros of x^2-9x-43=27 are x=14,x=-5