What are the solutions to the equation (4x+3)^2=18 ?

The solutions to the equation (4x+3)^2=18 are x=(3sqrt(2)-3)/4 ,x=(-3sqrt(2)-3)/4

Find the zeros of (4x+3)^2=18

The zeros of (4x+3)^2=18 are x=(3sqrt(2)-3)/4 ,x=(-3sqrt(2)-3)/4

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(4 x + 3)^{2} = 18

x = \frac{3 2 - 3}{4}, x = \frac{- 3 2 - 3}{4}

Decimal Notation

x = 0.31066 \dots, x = - 1.81066 \dots

Solution steps

(4 x + 3)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 3 = 18 : x = \frac{3 2 - 3}{4}

Solve

4 x + 3 = - 18 : x = \frac{- 3 2 - 3}{4}

The solutions to the quadratic equation are:

x = \frac{3 2 - 3}{4}, x = \frac{- 3 2 - 3}{4}

0.02 (0.5 x^{2} - x) = 0, 25

x, zy = x^{2}

x^{2} - 7 x = - 3

5 p^{2} - 14 p = 24

(x) = 300 - x + \frac{( x - 100 ) ^{2}}{250}

What are the solutions to the equation (4x+3)^2=18 ?
The solutions to the equation (4x+3)^2=18 are x=(3sqrt(2)-3)/4 ,x=(-3sqrt(2)-3)/4
Find the zeros of (4x+3)^2=18
The zeros of (4x+3)^2=18 are x=(3sqrt(2)-3)/4 ,x=(-3sqrt(2)-3)/4