What are the solutions to the equation x^2+12x+936=0 ?

The solutions to the equation x^2+12x+936=0 are x=-6+30i,x=-6-30i

Find the zeros of x^2+12x+936=0

The zeros of x^2+12x+936=0 are x=-6+30i,x=-6-30i

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x^{2} + 12 x + 936 = 0

x = - 6 + 30 i, x = - 6 - 30 i

Solution steps

x^{2} + 12 x + 936 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 936}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 936 : 60 i

x_{1, 2} = \frac{- 12 \pm 60 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 60 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 60 i}{2 \cdot 1}

x = \frac{- 12 + 60 i}{2 \cdot 1} : - 6 + 30 i

x = \frac{- 12 - 60 i}{2 \cdot 1} : - 6 - 30 i

The solutions to the quadratic equation are:

x = - 6 + 30 i, x = - 6 - 30 i

5 x^{2} + x - 18 = 0

x = x^{2} + 2

a^{2} - a - 7 = 0

(3 x - 1)^{2} = 108

z^{2} - 4 z + 1 = 0

What are the solutions to the equation x^2+12x+936=0 ?
The solutions to the equation x^2+12x+936=0 are x=-6+30i,x=-6-30i
Find the zeros of x^2+12x+936=0
The zeros of x^2+12x+936=0 are x=-6+30i,x=-6-30i