What are the solutions to the equation 3x^2-84x+480=0 ?

The solutions to the equation 3x^2-84x+480=0 are x=20,x=8

Find the zeros of 3x^2-84x+480=0

The zeros of 3x^2-84x+480=0 are x=20,x=8

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3 x^{2} - 84 x + 480 = 0

x = 20, x = 8

Solution steps

3 x^{2} - 84 x + 480 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 84 ) \pm ( - 84 ) ^{2} - 4 \cdot 3 \cdot 480}{2 \cdot 3}

(- 84)^{2} - 4 \cdot 3 \cdot 480 = 36

x_{1, 2} = \frac{- ( - 84 ) \pm 36}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 84 ) + 36}{2 \cdot 3}, x_{2} = \frac{- ( - 84 ) - 36}{2 \cdot 3}

x = \frac{- ( - 84 ) + 36}{2 \cdot 3} : 20

x = \frac{- ( - 84 ) - 36}{2 \cdot 3} : 8

The solutions to the quadratic equation are:

x = 20, x = 8

14 p^{2} + p - 6 = 2 p^{2}

- 63 x^{2} - 3 x + 6 = 0

(x + 9)^{2} + 8 (x + 9) + 7 = 0

- 45 = 0 + 10 t + \frac{1}{2} (- 9.8) t^{2}

4 (x - 7)^{2} + 25 = 69

What are the solutions to the equation 3x^2-84x+480=0 ?
The solutions to the equation 3x^2-84x+480=0 are x=20,x=8
Find the zeros of 3x^2-84x+480=0
The zeros of 3x^2-84x+480=0 are x=20,x=8