What are the solutions to the equation -63x^2-3x+6=0 ?

The solutions to the equation -63x^2-3x+6=0 are x=-1/3 ,x= 2/7

Find the zeros of -63x^2-3x+6=0

The zeros of -63x^2-3x+6=0 are x=-1/3 ,x= 2/7

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- 63 x^{2} - 3 x + 6 = 0

x = - \frac{1}{3}, x = \frac{2}{7}

Decimal Notation

x = - 0.33333 \dots, x = 0.28571 \dots

Solution steps

- 63 x^{2} - 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 63 ) \cdot 6}{2 ( - 63 )}

(- 3)^{2} - 4 (- 63) \cdot 6 = 39

x_{1, 2} = \frac{- ( - 3 ) \pm 39}{2 ( - 63 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 39}{2 ( - 63 )}, x_{2} = \frac{- ( - 3 ) - 39}{2 ( - 63 )}

x = \frac{- ( - 3 ) + 39}{2 ( - 63 )} : - \frac{1}{3}

x = \frac{- ( - 3 ) - 39}{2 ( - 63 )} : \frac{2}{7}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = \frac{2}{7}

(x + 9)^{2} + 8 (x + 9) + 7 = 0

- 45 = 0 + 10 t + \frac{1}{2} (- 9.8) t^{2}

4 (x - 7)^{2} + 25 = 69

3 r^{2} - 4050 r + 1362500 = 0

(3 x - 4)^{2} + 17 x = 35

What are the solutions to the equation -63x^2-3x+6=0 ?
The solutions to the equation -63x^2-3x+6=0 are x=-1/3 ,x= 2/7
Find the zeros of -63x^2-3x+6=0
The zeros of -63x^2-3x+6=0 are x=-1/3 ,x= 2/7