What are the solutions to the equation 3x^2+16x-75=0 ?

The solutions to the equation 3x^2+16x-75=0 are x=3,x=-25/3

Find the zeros of 3x^2+16x-75=0

The zeros of 3x^2+16x-75=0 are x=3,x=-25/3

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3 x^{2} + 16 x - 75 = 0

x = 3, x = - \frac{25}{3}

Decimal Notation

x = 3, x = - 8.33333 \dots

Solution steps

3 x^{2} + 16 x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 ( - 75 )}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 (- 75) = 34

x_{1, 2} = \frac{- 16 \pm 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 16 + 34}{2 \cdot 3}, x_{2} = \frac{- 16 - 34}{2 \cdot 3}

x = \frac{- 16 + 34}{2 \cdot 3} : 3

x = \frac{- 16 - 34}{2 \cdot 3} : - \frac{25}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{25}{3}

x, f^{- 1} (x) = (x + 3)^{2}

7 x^{2} - 4 = 3 x^{2} - 12

4.9 x^{2} - 40 x - 14 = 0

x, x^{2} + x + 4 = 0

3 x^{2} + 8 x = 2

What are the solutions to the equation 3x^2+16x-75=0 ?
The solutions to the equation 3x^2+16x-75=0 are x=3,x=-25/3
Find the zeros of 3x^2+16x-75=0
The zeros of 3x^2+16x-75=0 are x=3,x=-25/3