What are the solutions to the equation -x^2-4x-8=0 ?

The solutions to the equation -x^2-4x-8=0 are x=-2-2i,x=-2+2i

Find the zeros of -x^2-4x-8=0

The zeros of -x^2-4x-8=0 are x=-2-2i,x=-2+2i

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- x^{2} - 4 x - 8 = 0

x = - 2 - 2 i, x = - 2 + 2 i

Solution steps

- x^{2} - 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

Simplify

(- 4)^{2} - 4 (- 1) (- 8) : 4 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 4 i}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 4 i}{2 ( - 1 )} : - 2 - 2 i

x = \frac{- ( - 4 ) - 4 i}{2 ( - 1 )} : - 2 + 2 i

The solutions to the quadratic equation are:

x = - 2 - 2 i, x = - 2 + 2 i

- 3 x^{2} + 80 x + 27 = 0

y^{2} - 4 y - 96 = 0

y, y^{2} = c x^{4} + 3 x

3 (x - 7)^{2} = 12

λ^{2} - λ - 12 = 0

What are the solutions to the equation -x^2-4x-8=0 ?
The solutions to the equation -x^2-4x-8=0 are x=-2-2i,x=-2+2i
Find the zeros of -x^2-4x-8=0
The zeros of -x^2-4x-8=0 are x=-2-2i,x=-2+2i