What are the solutions to the equation 2x^2+x-72=0 ?

The solutions to the equation 2x^2+x-72=0 are x=(-1+sqrt(577))/4 ,x=(-1-sqrt(577))/4

Find the zeros of 2x^2+x-72=0

The zeros of 2x^2+x-72=0 are x=(-1+sqrt(577))/4 ,x=(-1-sqrt(577))/4

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2 x^{2} + x - 72 = 0

x = \frac{- 1 + 577}{4}, x = \frac{- 1 - 577}{4}

Decimal Notation

x = 5.75520 \dots, x = - 6.25520 \dots

Solution steps

2 x^{2} + x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 72 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 72) = 577

x_{1, 2} = \frac{- 1 \pm 577}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 577}{2 \cdot 2}, x_{2} = \frac{- 1 - 577}{2 \cdot 2}

x = \frac{- 1 + 577}{2 \cdot 2} : \frac{- 1 + 577}{4}

x = \frac{- 1 - 577}{2 \cdot 2} : \frac{- 1 - 577}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 577}{4}, x = \frac{- 1 - 577}{4}

x^{2} - 1 = 7 - x^{2}

- 3 (x + 5)^{2} = 12

x, x^{2} - 2 x - 2 = 0

3 s^{2} + 18 s + 14 = 0

x, z = x^{2} y + 1

What are the solutions to the equation 2x^2+x-72=0 ?
The solutions to the equation 2x^2+x-72=0 are x=(-1+sqrt(577))/4 ,x=(-1-sqrt(577))/4
Find the zeros of 2x^2+x-72=0
The zeros of 2x^2+x-72=0 are x=(-1+sqrt(577))/4 ,x=(-1-sqrt(577))/4