What are the solutions to the equation (3x+10)^2+81=0 ?

The solutions to the equation (3x+10)^2+81=0 are x=-10/3+3i,x=-10/3-3i

Find the zeros of (3x+10)^2+81=0

The zeros of (3x+10)^2+81=0 are x=-10/3+3i,x=-10/3-3i

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(3 x + 10)^{2} + 81 = 0

x = - \frac{10}{3} + 3 i, x = - \frac{10}{3} - 3 i

Solution steps

(3 x + 10)^{2} + 81 = 0

Move

81

to the right side

(3 x + 10)^{2} = - 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 10 = - 81 : x = - \frac{10}{3} + 3 i

Solve

3 x + 10 = - - 81 : x = - \frac{10}{3} - 3 i

The solutions to the quadratic equation are:

x = - \frac{10}{3} + 3 i, x = - \frac{10}{3} - 3 i

x, 500 \cdot x^{2} - (500 \cdot x) = 1000

600 = - q^{2} + 1000

x^{2} - \frac{2}{5} x + \frac{1}{25} = 0

r^{2} - 9 r + 20 = 0

- 4 x^{2} - 12 x + 10 = 0

What are the solutions to the equation (3x+10)^2+81=0 ?
The solutions to the equation (3x+10)^2+81=0 are x=-10/3+3i,x=-10/3-3i
Find the zeros of (3x+10)^2+81=0
The zeros of (3x+10)^2+81=0 are x=-10/3+3i,x=-10/3-3i