What are the solutions to the equation -x^2+2x=8 ?

The solutions to the equation -x^2+2x=8 are x=1-sqrt(7)i,x=1+sqrt(7)i

Find the zeros of -x^2+2x=8

The zeros of -x^2+2x=8 are x=1-sqrt(7)i,x=1+sqrt(7)i

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- x^{2} + 2 x = 8

x = 1 - 7 i, x = 1 + 7 i

Solution steps

- x^{2} + 2 x = 8

Move

8

to the left side

- x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 8) : 27 i

x_{1, 2} = \frac{- 2 \pm 2 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 7 i}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 7 i}{2 ( - 1 )}

x = \frac{- 2 + 2 7 i}{2 ( - 1 )} : 1 - 7 i

x = \frac{- 2 - 2 7 i}{2 ( - 1 )} : 1 + 7 i

The solutions to the quadratic equation are:

x = 1 - 7 i, x = 1 + 7 i

8 n^{2} = 64 n

(3 x + 10)^{2} + 81 = 0

x, 500 \cdot x^{2} - (500 \cdot x) = 1000

600 = - q^{2} + 1000

x^{2} - \frac{2}{5} x + \frac{1}{25} = 0

What are the solutions to the equation -x^2+2x=8 ?
The solutions to the equation -x^2+2x=8 are x=1-sqrt(7)i,x=1+sqrt(7)i
Find the zeros of -x^2+2x=8
The zeros of -x^2+2x=8 are x=1-sqrt(7)i,x=1+sqrt(7)i