What are the solutions to the equation 2t^2-7t-15=0 ?

The solutions to the equation 2t^2-7t-15=0 are t=5,t=-3/2

Find the zeros of 2t^2-7t-15=0

The zeros of 2t^2-7t-15=0 are t=5,t=-3/2

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2 t^{2} - 7 t - 15 = 0

t = 5, t = - \frac{3}{2}

Decimal Notation

t = 5, t = - 1.5

Solution steps

2 t^{2} - 7 t - 15 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 15) = 13

t_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 2}, t_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 2}

t = \frac{- ( - 7 ) + 13}{2 \cdot 2} : 5

t = \frac{- ( - 7 ) - 13}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

t = 5, t = - \frac{3}{2}

x^{2} + 15 x = - 54

3 x^{2} - 7 x - 9 = 0

(m^{2} - 1) x^{2} + 9 = 2 (3 m + 1) x

x, (\frac{x}{2})^{2} + y^{2} = r^{2}

x^{2} + 10 x + 9 = - 7

What are the solutions to the equation 2t^2-7t-15=0 ?
The solutions to the equation 2t^2-7t-15=0 are t=5,t=-3/2
Find the zeros of 2t^2-7t-15=0
The zeros of 2t^2-7t-15=0 are t=5,t=-3/2