What are the solutions to the equation solvefor x,(x/2)^2+y^2=r^2 ?

The solutions to the equation solvefor x,(x/2)^2+y^2=r^2 are x=2sqrt(r^2-y^2),x=-2sqrt(r^2-y^2)

Find the zeros of solvefor x,(x/2)^2+y^2=r^2

The zeros of solvefor x,(x/2)^2+y^2=r^2 are x=2sqrt(r^2-y^2),x=-2sqrt(r^2-y^2)

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solve for

x, (\frac{x}{2})^{2} + y^{2} = r^{2}

x = 2 r^{2} - y^{2}, x = - 2 r^{2} - y^{2}

Solution steps

(\frac{x}{2})^{2} + y^{2} = r^{2}

Move

y^{2}

to the right side

(\frac{x}{2})^{2} = r^{2} - y^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{x}{2} = r^{2} - y^{2} : x = 2 r^{2} - y^{2}

Solve

\frac{x}{2} = - r^{2} - y^{2} : x = - 2 r^{2} - y^{2}

The solutions to the quadratic equation are:

x = 2 r^{2} - y^{2}, x = - 2 r^{2} - y^{2}

x^{2} + 10 x + 9 = - 7

m^{2} + 27 = - 12 m

x^{2} + 6 x - 1 = 0

x, 2 x^{2} + 4 x y + 2 y^{2} - 5 x + 4 y + 7 = 0

x (12 - x) = 2 x^{2} - 8

What are the solutions to the equation solvefor x,(x/2)^2+y^2=r^2 ?
The solutions to the equation solvefor x,(x/2)^2+y^2=r^2 are x=2sqrt(r^2-y^2),x=-2sqrt(r^2-y^2)
Find the zeros of solvefor x,(x/2)^2+y^2=r^2
The zeros of solvefor x,(x/2)^2+y^2=r^2 are x=2sqrt(r^2-y^2),x=-2sqrt(r^2-y^2)