What are the solutions to the equation 3x^2-7x-9=0 ?

The solutions to the equation 3x^2-7x-9=0 are x=(7+sqrt(157))/6 ,x=(7-sqrt(157))/6

Find the zeros of 3x^2-7x-9=0

The zeros of 3x^2-7x-9=0 are x=(7+sqrt(157))/6 ,x=(7-sqrt(157))/6

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3 x^{2} - 7 x - 9 = 0

x = \frac{7 + 157}{6}, x = \frac{7 - 157}{6}

Decimal Notation

x = 3.25499 \dots, x = - 0.92166 \dots

Solution steps

3 x^{2} - 7 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 9) = 157

x_{1, 2} = \frac{- ( - 7 ) \pm 157}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 157}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 157}{2 \cdot 3}

x = \frac{- ( - 7 ) + 157}{2 \cdot 3} : \frac{7 + 157}{6}

x = \frac{- ( - 7 ) - 157}{2 \cdot 3} : \frac{7 - 157}{6}

The solutions to the quadratic equation are:

x = \frac{7 + 157}{6}, x = \frac{7 - 157}{6}

(m^{2} - 1) x^{2} + 9 = 2 (3 m + 1) x

x, (\frac{x}{2})^{2} + y^{2} = r^{2}

x^{2} + 10 x + 9 = - 7

m^{2} + 27 = - 12 m

x^{2} + 6 x - 1 = 0

What are the solutions to the equation 3x^2-7x-9=0 ?
The solutions to the equation 3x^2-7x-9=0 are x=(7+sqrt(157))/6 ,x=(7-sqrt(157))/6
Find the zeros of 3x^2-7x-9=0
The zeros of 3x^2-7x-9=0 are x=(7+sqrt(157))/6 ,x=(7-sqrt(157))/6