What are the solutions to the equation 2x(x+2)=3 ?

The solutions to the equation 2x(x+2)=3 are x=(-2+sqrt(10))/2 ,x=-(2+sqrt(10))/2

Find the zeros of 2x(x+2)=3

The zeros of 2x(x+2)=3 are x=(-2+sqrt(10))/2 ,x=-(2+sqrt(10))/2

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2 x (x + 2) = 3

x = \frac{- 2 + 10}{2}, x = - \frac{2 + 10}{2}

Decimal Notation

x = 0.58113 \dots, x = - 2.58113 \dots

Solution steps

2 x (x + 2) = 3

Expand

2 x (x + 2) : 2 x^{2} + 4 x

2 x^{2} + 4 x = 3

Move

3

to the left side

2 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 3) = 210

x_{1, 2} = \frac{- 4 \pm 2 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 2 10}{2 \cdot 2}, x_{2} = \frac{- 4 - 2 10}{2 \cdot 2}

x = \frac{- 4 + 2 10}{2 \cdot 2} : \frac{- 2 + 10}{2}

x = \frac{- 4 - 2 10}{2 \cdot 2} : - \frac{2 + 10}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 10}{2}, x = - \frac{2 + 10}{2}

2 x^{2} - 4 x = 3 x + 4

4 c^{2} + 10 c^{2} = 29 + 1

2 x^{2} + 5 x = 2

10 x^{2} + x - 1 = 0

3 y^{2} - 108 = 0

What are the solutions to the equation 2x(x+2)=3 ?
The solutions to the equation 2x(x+2)=3 are x=(-2+sqrt(10))/2 ,x=-(2+sqrt(10))/2
Find the zeros of 2x(x+2)=3
The zeros of 2x(x+2)=3 are x=(-2+sqrt(10))/2 ,x=-(2+sqrt(10))/2