What are the solutions to the equation solvefor x,x^2-2xy+y^2-6x+2y=0 ?

The solutions to the equation solvefor x,x^2-2xy+y^2-6x+2y=0 are x=y+3+sqrt(4y+9),x=y+3-sqrt(4y+9)

Find the zeros of solvefor x,x^2-2xy+y^2-6x+2y=0

The zeros of solvefor x,x^2-2xy+y^2-6x+2y=0 are x=y+3+sqrt(4y+9),x=y+3-sqrt(4y+9)

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solve for

x, x^{2} - 2 x y + y^{2} - 6 x + 2 y = 0

x = y + 3 + 4 y + 9, x = y + 3 - 4 y + 9

Solution steps

x^{2} - 2 x y + y^{2} - 6 x + 2 y = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - (2 y + 6) x + y^{2} + 2 y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 y - 6 ) \pm ( - 2 y - 6 ) ^{2} - 4 \cdot 1 \cdot ( y ^{2} + 2 y )}{2 \cdot 1}

Simplify

(- 2 y - 6)^{2} - 4 \cdot 1 \cdot (y^{2} + 2 y) : 2 4 y + 9

x_{1, 2} = \frac{- ( - 2 y - 6 ) \pm 2 4 y + 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 y - 6 ) + 2 4 y + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 2 y - 6 ) - 2 4 y + 9}{2 \cdot 1}

x = \frac{- ( - 2 y - 6 ) + 2 4 y + 9}{2 \cdot 1} : y + 3 + 4 y + 9

x = \frac{- ( - 2 y - 6 ) - 2 4 y + 9}{2 \cdot 1} : y + 3 - 4 y + 9

The solutions to the quadratic equation are:

x = y + 3 + 4 y + 9, x = y + 3 - 4 y + 9

x^{2} - 3 x = 3

(x + 8) (x - 6) = 627

x^{2} + 10 x + 22 = 0

3^{2} = 2^{2} + b^{2}

- 0.6 (x - 2.5)^{2} + 8.75 = 0

What are the solutions to the equation solvefor x,x^2-2xy+y^2-6x+2y=0 ?
The solutions to the equation solvefor x,x^2-2xy+y^2-6x+2y=0 are x=y+3+sqrt(4y+9),x=y+3-sqrt(4y+9)
Find the zeros of solvefor x,x^2-2xy+y^2-6x+2y=0
The zeros of solvefor x,x^2-2xy+y^2-6x+2y=0 are x=y+3+sqrt(4y+9),x=y+3-sqrt(4y+9)