What are the solutions to the equation 3u^2-2=5u ?

The solutions to the equation 3u^2-2=5u are u=2,u=-1/3

Find the zeros of 3u^2-2=5u

The zeros of 3u^2-2=5u are u=2,u=-1/3

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3 u^{2} - 2 = 5 u

u = 2, u = - \frac{1}{3}

Decimal Notation

u = 2, u = - 0.33333 \dots

Solution steps

3 u^{2} - 2 = 5 u

Move

5 u

to the left side

3 u^{2} - 2 - 5 u = 0

Write in the standard form

a x^{2} + b x + c = 0

3 u^{2} - 5 u - 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 2) = 7

u_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 3}, u_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 3}

u = \frac{- ( - 5 ) + 7}{2 \cdot 3} : 2

u = \frac{- ( - 5 ) - 7}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

u = 2, u = - \frac{1}{3}

x^{2} + (\frac{2}{2})^{2} = 1

- 3 x^{2} + 6 x + 1 = 0

- 2 y^{2} + 30 y = 0

- x^{2} + 4 x = - 12

C (t) = - 0.0002 t^{2} + 0.06 t, 0 \leq t \leq 240

What are the solutions to the equation 3u^2-2=5u ?
The solutions to the equation 3u^2-2=5u are u=2,u=-1/3
Find the zeros of 3u^2-2=5u
The zeros of 3u^2-2=5u are u=2,u=-1/3