What are the solutions to the equation x^2-105x+2700=0 ?

The solutions to the equation x^2-105x+2700=0 are x=60,x=45

Find the zeros of x^2-105x+2700=0

The zeros of x^2-105x+2700=0 are x=60,x=45

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x^{2} - 105 x + 2700 = 0

x = 60, x = 45

Solution steps

x^{2} - 105 x + 2700 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 105 ) \pm ( - 105 ) ^{2} - 4 \cdot 1 \cdot 2700}{2 \cdot 1}

(- 105)^{2} - 4 \cdot 1 \cdot 2700 = 15

x_{1, 2} = \frac{- ( - 105 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 105 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 105 ) - 15}{2 \cdot 1}

x = \frac{- ( - 105 ) + 15}{2 \cdot 1} : 60

x = \frac{- ( - 105 ) - 15}{2 \cdot 1} : 45

The solutions to the quadratic equation are:

x = 60, x = 45

X^{2} - 3 (2 X - 5) = 10

n^{2} = 20 - n

x, x^{2} + p x + 12 = 0

x^{2} - \frac{81}{4} = 0

t, - \frac{1}{2} \cdot g \cdot t^{2} + v \cdot t = 0

What are the solutions to the equation x^2-105x+2700=0 ?
The solutions to the equation x^2-105x+2700=0 are x=60,x=45
Find the zeros of x^2-105x+2700=0
The zeros of x^2-105x+2700=0 are x=60,x=45