What are the solutions to the equation -4x^2-24x-32=0 ?

The solutions to the equation -4x^2-24x-32=0 are x=-4,x=-2

Find the zeros of -4x^2-24x-32=0

The zeros of -4x^2-24x-32=0 are x=-4,x=-2

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- 4 x^{2} - 24 x - 32 = 0

x = - 4, x = - 2

Solution steps

- 4 x^{2} - 24 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 4 ) ( - 32 )}{2 ( - 4 )}

(- 24)^{2} - 4 (- 4) (- 32) = 8

x_{1, 2} = \frac{- ( - 24 ) \pm 8}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8}{2 ( - 4 )}, x_{2} = \frac{- ( - 24 ) - 8}{2 ( - 4 )}

x = \frac{- ( - 24 ) + 8}{2 ( - 4 )} : - 4

x = \frac{- ( - 24 ) - 8}{2 ( - 4 )} : - 2

The solutions to the quadratic equation are:

x = - 4, x = - 2

x, 4 x + x^{2} y = y

\frac{6 x - 7}{4} \frac{3 x - 5}{7} = \frac{5 x 78}{28}

(x - 3)^{2} + (x - 3)^{2} = 25

9 m^{2} - 12 m - 2 = 0

6^{2} + b^{2} = 1 1^{2}

What are the solutions to the equation -4x^2-24x-32=0 ?
The solutions to the equation -4x^2-24x-32=0 are x=-4,x=-2
Find the zeros of -4x^2-24x-32=0
The zeros of -4x^2-24x-32=0 are x=-4,x=-2